Powerfactor Improvement Calculator facebook twitter youtube

Ho to use this calculator?

Step 1: There are 3 types of powerfactor correction calculator. Select a radio button among Type 1, Type 2 or Type 3 base on your input and desire paramiters.
Step 2: Change delault input values as your problem values.
Step 3: Hit the Calculate button and see results.

You have to select Type 1 or Type 2 or Type 3
Type 1
Real power in kilowatts, P = KW
Initial P.F. = cosφ1
Desired P.F. = cosφ2
Capacitor KVAR = ?
Type 2
Real power in kilowatts, P = KW
Initial P.F. = cosφ1
Desired P.F. = cosφ2
Capacitor KVAR = ?
Increase KW = ?
Type 3
Rated Voltage = V
Input Current = I
Frequency = Hz
Initial P.F. = cosφ1
Desired P.F. = cosφ2
Capacitor KVAR = ?
Capacitor Value = ?
Increase KW = ?

Example of Type 1 calculator:

Given that,

Real power in kilowatts, P = 3 KW
Initial P.F. = Cosφ1 = 0.75
Desired P.F = Cosφ2 = 0.90
Capacitor KVAR = ?

Solution:
φ1 = Cos-1 = (0.75) = 41.41°; tan φ1 = tan (41.41°) = 0.8819
φ2 = Cos-1 = (0.90) = 25.84°; tan φ2 = tan (25.50°) = 0.4843

So, Capacitor KVAR to initial P.F 0.75 to desired P.F. 0.90
Capacitor KVAR = P * (tan φ1 – tan φ2)
= 3 * (0.8819 – 0.4843)
= 1.193 KVAR
Ans: Capacitor KVAR = 1.193

 

Example of Type 2 calculator:

P = 10 KW
Cosφ1 = 0.65
Cosφ2 = 0.95
Capacitor KVAR = ?
Increase KW = ?

Solution:
φ1 = Cos-1 = (0.65) = 49.46°; tan φ1 = tan (49.46°) = 1.169
φ2 = Cos-1 = (0.95) = 18.19°; tan φ2 = tan (25.50°) = 0.329

So, Capacitor KVAR to initial P.F 0.65 to desired P.F. 0.95
Capacitor KV= P * (tan φ1 – tan φ2)
= 3 * (1.169 – 0.329)
= 8.404 KVAR

At P.F. = 0.65 :
Reactive Power, Q = P*tan φ1
= 10*1.168
= 11.687 KVAR

At P.F. = 0.95 :
Real Power, P = P.F. * Q
= 0.95 * 11.687
= 11.1055 KW

Increase of Real Power = (11.1055 - 10) = 1.1055

Ans: Capacitor KVAR Q = 8.404
Increaseed Real Power in KW , P = 1.1055

 

Example of Type 3 calculator:

Rated Voltage = 240 v
Input Current = 20 A
Cosφ1 = 0.8
Cosφ2 = 0.9
Capacitor KVAR = ?
Increase KW = ?
Capacitor Value = ?

Solution:
Input Real Power at P.F.= 0.8,
P1 = V*I*Cosφ1 = 240*20*0.8 = 3.84 KW

φ1 = Cos-1 = (0.8) = 36.87°; tan φ1 = tan (36.87°) = 0.75
φ2 = Cos-1 = (0.9) = 25.84°; tan φ2 = tan (25.84°) = 0.484

So, Capacitor KVAR to initial P.F 0.8 to desired P.F. 0.9
Capacitor KV = P1 * (tan φ1 – tan φ2)
= 3.84 * (0.75 – 0.484)
= 1.02 KVAR

At P.F. = 0.8 :
Reactive Power, Q = Real Power/P.F
= 3.84/.8
= 4.8 KVAR

At P.F. = 0.9 :
Real Power, P = P.F. * Q
= 0.9 * 4.8
= 4.32 KW

Increase of Real Power = (4.8 - 4.32) = 0.48 KW

We know,
Capacitive reactance Xc = V2/Q
Xc = 2402/1.02K = 56.47 Ohms

Again,
C = 1/(2*pi*f*Xc)
= 1/(2*pi*50*12)
= 56.379 uF

Ans: Capacitor KVAR Q = 1.02
Increaseed Real Power in KW , P = 0.48
Capacitor value = 56.379 uF

Newsletter and Subscription

Our aim
"To provide essential calculators and make simple your mathematical problems such as science and engineering, finance, health is our aim, that fully meet your requirements."

What does people say?
" I'm studying Electrical and Electronics Engineering (EEE), and the Transformer calculator is very helpful to me."

"The weight loss calculator gives me a clear concept that how much calories do I need to take each day."


Subscription

Most popular calculator

  • Transformer Problem Solving Calculator
  • Numerical Analysis Calculator
  • Electric Bill Calculator
  • Mortgage Calculator

Contact us

AZ Calculator
Skype:   azcalculator
Email: azcalculator@gmail.com
Link: www.azcalculator.com

Quick Links
Services
About us
Portfolio
Find us on

Copywrite @ Anwar IT & Web Programming 2009, All Right Reserved