**Step 1:** There are 3 types of powerfactor correction calculator. **Select a radio button** among Type 1, Type 2 or Type 3 base on your input and desire paramiters.

**Step 2:** Change delault input values as your problem values.

**Step 3:** Hit the Calculate button and see results.

Given that,

Real power in kilowatts, P = 3 KW

Initial P.F. = Cosφ1 = 0.75

Desired P.F = Cosφ2 = 0.90

Capacitor KVAR = ?

**Solution:**

φ1 = Cos-1 = (0.75) = 41.41°; tan φ1 = tan (41.41°) = 0.8819

φ2 = Cos-1 = (0.90) = 25.84°; tan φ2 = tan (25.50°) = 0.4843

So, Capacitor KVAR to initial P.F 0.75 to desired P.F. 0.90

Capacitor KVAR = P * (tan φ1 – tan φ2)

= 3 * (0.8819 – 0.4843)

= 1.193 KVAR

**Ans: Capacitor KVAR = 1.193**

P = 10 KW

Cosφ1 = 0.65

Cosφ2 = 0.95

Capacitor KVAR = ?

Increase KW = ?

**Solution:**

φ1 = Cos-1 = (0.65) = 49.46°; tan φ1 = tan (49.46°) = 1.169

φ2 = Cos-1 = (0.95) = 18.19°; tan φ2 = tan (25.50°) = 0.329

So, Capacitor KVAR to initial P.F 0.65 to desired P.F. 0.95

Capacitor KV= P * (tan φ1 – tan φ2)

= 3 * (1.169 – 0.329)

= 8.404 KVAR

At P.F. = 0.65 :

Reactive Power, Q = P*tan φ1

= 10*1.168

= 11.687 KVAR

At P.F. = 0.95 :

Real Power, P = P.F. * Q

= 0.95 * 11.687

= 11.1055 KW

Increase of Real Power = (11.1055 - 10) = 1.1055

**Ans: Capacitor KVAR Q = 8.404
Increaseed Real Power in KW , P = 1.1055 **

Rated Voltage = 240 v

Input Current = 20 A

Cosφ1 = 0.8

Cosφ2 = 0.9

Capacitor KVAR = ?

Increase KW = ?

Capacitor Value = ?

**Solution:**

Input Real Power at P.F.= 0.8,

P1 = V*I*Cosφ1 = 240*20*0.8 = 3.84 KW

φ1 = Cos-1 = (0.8) = 36.87°; tan φ1 = tan (36.87°) = 0.75

φ2 = Cos-1 = (0.9) = 25.84°; tan φ2 = tan (25.84°) = 0.484

So, Capacitor KVAR to initial P.F 0.8 to desired P.F. 0.9

Capacitor KV = P1 * (tan φ1 – tan φ2)

= 3.84 * (0.75 – 0.484)

= 1.02 KVAR

At P.F. = 0.8 :

Reactive Power, Q = Real Power/P.F

= 3.84/.8

= 4.8 KVAR

At P.F. = 0.9 :

Real Power, P = P.F. * Q

= 0.9 * 4.8

= 4.32 KW

Increase of Real Power = (4.8 - 4.32) = 0.48 KW

We know,

Capacitive reactance Xc = V^{2}/Q

Xc = 240^{2}/1.02K = 56.47 Ohms

Again,

C = 1/(2*pi*f*Xc)

= 1/(2*pi*50*12)

= 56.379 uF

**Ans: Capacitor KVAR Q = 1.02
Increaseed Real Power in KW , P = 0.48
Capacitor value = 56.379 uF**